The value of 'spin only' magnetic moment for | vedclass

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Question

(B) The formula for 'spin only' magnetic moment is $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. Given $\sqrt{n(n+2)} = 2.

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$d^4$ (in strong field ligand)

Vedclass · Answer

(B) The formula for 'spin only' magnetic moment is $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. Given $\sqrt{n(n+2)} = 2.84$,squaring both sides gives $n(n+2) \approx 8$,which implies $n = 2$. For a $d^4$ configuration in a strong field ligand,the electrons pair up in the $t_{2g}$ orbitals,leaving $2$ unpaired electrons $(t_{2g}^4 e_g^0)$. Thus,$n = 2$ corresponds to the $d^4$ strong field configuration.

The value of 'spin only' magnetic moment for one of the following configurations is $2.84 \ BM$. The correct one is:

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